P-value for enrichment of ChIP-Seq peaks within a genomic annotation
1
1
Entering edit mode
9.1 years ago
User 7754 ▴ 270

Hi,

I am trying to find a p-value for enrichment of ChIP-Seq peaks from a bed file within a chromatin state from the UCSC stored in another bed file. I overlapped the two bed files using BedTools and now I have these values:

The number of ChiP-Seq peaks that overlap a chromatin state (more than one peak can overlap a chromatin state, but a specific peak belongs to only one chromatin state)= 10450

The total number of ChiP-Seq peaks = 100561

The total coverage of a chromatin state = 204652

How can I get a p-value of enrichment for the CHiP-Seq peak within the chromatin state?

Thank you

ChIP-Seq • 4.2k views
ADD COMMENT
0
Entering edit mode

This biostar answer is quite comprehensive. Personally, I had used the bedtools fisher, you'll need your list of peaks, your list of chromatin states and a file with the chromosome sizes.

ADD REPLY
0
Entering edit mode
9.1 years ago
dally ▴ 210

Have you thought about the phyper function in R?

ADD COMMENT
0
Entering edit mode

Hi and thanks for the reply!

I have, but I am not sure what I would use for the totals including the non-overlapping peaks and annotations, would this be correct?

phyper(10450, 100561, 100561+204652, 204652-100561)
ADD REPLY
0
Entering edit mode

Probability of gene list overlap

See if this helps you, I'd give you specifics but I'm not comfortable enough with my knowledge of this function to do that.

ADD REPLY
0
Entering edit mode

Thanks this helps, but I am still confused about what our k would be, if we consider the number of ChiP-Seq peaks:

q=10450-1, m=100561, n=204652, k=204652?

Also would it not be important to consider that more than one ChIP peak can overlap each chromatin state?

ADD REPLY

Login before adding your answer.

Traffic: 1512 users visited in the last hour
Help About
FAQ
Access RSS
API
Stats

Use of this site constitutes acceptance of our User Agreement and Privacy Policy.

Powered by the version 2.3.6