Understanding a VCF - Genotype likelihoods and genotype call
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6.4 years ago
cetin.m ▴ 50

I calculated genotype likelihoods from a BAM file with the command: "samtools mpileup -g -f filename" and got the BCF file.

Then I used "bcftools call -c -v filename" to get the VCF.

In the VCF file, I see the following two:

1 589051 . G A 7.79993 . DP=1;SGB=-0.379885;MQ0F=0;AF1=1;AC1=2;DP4=0,0,1,0;MQ=37;FQ=-29.991 GT:PL 1/1:37,3,0

1 700436 . G A 4.77219 . DP=1;SGB=-0.379885;MQ0F=0;AF1=1;AC1=2;DP4=0,0,0,1;MQ=37;FQ=-29.9923 GT:PL 0/1:33,3,0

In the top SNP I get that the most likely genotype is 1/1 (given by the lowest Phred score of 0). Therefore the called genotype is 1/1.

However in the below one even though the loweest Phred score of 0 belongs to the 1/1 genotype, the called genotype is given by 0/1.

What am I missing?

I am new so this is probably obvious to many.

Thanks.

sequence sequencing next-gen • 2.1k views
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both variants doesn't mean much things: they both have only one read(DP=1) overlapping the variant....

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I know. I am just trying to understand how the genotype likelihood part works.

Do you have a comment about that?

Thanks.

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