How to group some nucleotide sequences based on similarity.
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4.9 years ago

I have 20 nucleotide sequences of a particular gene. I collected these sequences from 20 different strains of a virus. My target is to separate them into different groups based on similarity. Finally, I will find out a consensus sequence from each group. How I can do this???

sequence alignment • 2.1k views
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By doing a multiple sequence alignment. You can use a local program like MEGA/clustal or an online web interface e.g. clustal omega.

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As far as I know, through MSA I will get only one consensus sequence for all 20 nucleotide sequences. But, I want to group the sequence first (maybe 3 or 4 groups), the most similar sequence will be put together and one consensus seq for each group. Actually I'm very new to Bioinformatics, maybe I am wrong.

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If you know which sequences are more homologous to each other, you could separate them before doing individual MSA's.

If you don't have an idea, then try doing an initial MSA with all sequences (since you said they are from a particular gene they should be reasonably homologous to do that alignment). Examine the results of the alignment (plot a distance tree) and then decide on the groups you want to break the sequences into before doing individual alignments to get a consensus.

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4.9 years ago
yairgatt ▴ 10

I am not certain what the question you are hoping to answer is, but your could cluster the sequences using a program like CD-HIT. If you are trying to assess the evolutionary linkage between the strains, it might be best to construct a dendrogram or a phylogenetic tree for these sequences.

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Thank you for your suggestion. My main target is clustering the sequences based on similarity. I think CD-HIT will be a solution.

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You have to keep in mind that cd-hit is going to cluster solely based on sequence. It will not take into consideration evolutionary relationships between sequences (or introduce gaps where needed).

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Luckily, I only need to group them based on similarity. I am not going to do any evolutionary analysis. Thank you for your help.

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