Replace a special character with another one in a string using Linux regex

Question

[eDNAuRNA]

Hi everyone,

I am trying to replace the first period by a hyphen in following strings by using regex (?<=\d\d)\.

12345.678910-68597-19_A250_M007_001_1_1.abcde.fg

I am using sed command as sed 's/(?<=\d\d)\./-/' To make the output as follows:

12345-678910-68597-19_A250_M007_001_1_1.abcde.fg

However, in Linux its not working.

Can anyone help where I am making a mistake?

Thanks

Answer 1

[Arup Ghosh]

One possible solution is capturing the part before and after . and joining them with a -.

sed 's/^\([0-9]\+\).\(.*\)/\1\-\2/' <text>