how to remove a substring for multiple file names?

Question

[v.berriosfarias]

Hello I have files with the following file names:

VIR3A_CCGCGGTT-CTAGCGCT_L00M_1.fastq.gz
VIR3A_CCGCGGTT-CTAGCGCT_L00M_2.fastq.gz
VIR3B_TTATAACC-TCGATATC_L00M_1.fastq.gz
VIR3B_TTATAACC-TCGATATC_L00M_2.fastq.gz

I want to delete all the "ACTGs" so I can have files like VIR3A_1.fastq.gz, VIR3A_2.fastq.gz and so on using bash

Thanks for your time :)

[cpad0112]

with rename

$ ls
VIR3A_CCGCGGTT-CTAGCGCT_L00M_1.fastq.gz  VIR3A_CCGCGGTT-CTAGCGCT_L00M_2.fastq.gz                                                                                                          

$ rename -nv 's/^(\w+_).*_(.*)$/$1$2/' *.gz

Using expression: sub { use feature ':5.32'; s/^(\w+_).*_(.*)$/$1$2/ }    
'VIR3A_CCGCGGTT-CTAGCGCT_L00M_1.fastq.gz' would be renamed to 'VIR3A_1.fastq.gz'
'VIR3A_CCGCGGTT-CTAGCGCT_L00M_2.fastq.gz' would be renamed to 'VIR3A_2.fastq.gz'

with bash

$ for i in *.fastq.gz; do echo $i ${i%%_*}_${i##*_}; done

VIR3A_CCGCGGTT-CTAGCGCT_L00M_1.fastq.gz VIR3A_1.fastq.gz
VIR3A_CCGCGGTT-CTAGCGCT_L00M_2.fastq.gz VIR3A_2.fastq.gz
VIR3B_TTATAACC-TCGATATC_L00M_1.fastq.gz VIR3B_1.fastq.gz
VIR3B_TTATAACC-TCGATATC_L00M_2.fastq.gz VIR3B_2.fastq.gz

[v.berriosfarias]

Thanks for your reply!, for curiosity, what the "%%" and the "##" do here?

Answer 1

[Pierre Lindenbaum]

ls *.fastq.gz | awk -F _ '{printf("mv \"%s\" \"%s_%s\"\n",$0,$1,$NF);}' > script.bash

check script.bash and the invoke it bash script.bash

[v.berriosfarias]

yeah this worked, thanks so much!!

Answer 2

[ATpoint]

for i in *.fastq.gz; do mv $i $(echo $i | awk -F "_" '{print $1"_"$4}'); done