LDSC correlation calculate confidence intervals

Question

[YL]

Hello,

I found that following formula asked by other colleagues but no answer:

zprime = 0.5 * log((1+rg) / (1-rg))

ci = zprime ± 1.96*se

ci = ((exp(2ci) - 1) / (exp(2ci) + 1))

(rg and se taken from the LDSC output)

I wonder if this is the correct way of calculating 95% CI from LDSC output?

Thank you very much!

[YL]

Hi,

Are you able to find an answer for this? I have the exact question!

YL

[YL]

Based on my personal thought, I think the se from LDSC output probably needs to be transferred using Delta method based on Fisher transformation, and then used the transformed se to do ci = zprime ± 1.96*se

Hopefully we will get confirmation soon