I'm using bcftools to extract variants from a bam file, but I have reference data that tells me whether the patient is homozygous or heterozygous. For a particular sample, I see a high proportion of the alternate allele (87%) and a lower proportion of the reference allele (13%), yet according to the reference data, this sample is heterozygous. When I pass this data to bcftools, it reports the presence of the allele but as if it were homozygous. Is there a way to simply get the abundance of the alternate and reference alleles? This is the code I am using
bcftools mpileup -Ou -f hg19.fasta IonXpress_006.bam --max-depth 10000 --threads 15| bcftools call -mv -Ov -o calls.vcf -v --threads 15 -P 0.1
And the results I'm getting
chr6 31239407 . G T 212.999 . DP=297;VDB=0;SGB=-0.693147;RPB=0.910997;MQB=0.0455166;MQSB=6.28864e-17;BQB=0.986643;MQ0F=0;AF1=1;AC1=2;DP4=25,12,180,76;MQ=33;FQ=-229.988;PV4=0.705928,1,0.142598,0.270096 GT:PL 1/1:246,203,0
chr6 31239417 . C T 187.999 . DP=296;VDB=0;SGB=-0.693147;RPB=0.933514;MQB=0.0575658;MQSB=9.14302e-18;BQB=0.0934661;MQ0F=0;AF1=1;AC1=2;DP4=24,13,182,76;MQ=33;FQ=-231.988;PV4=0.565766,0.202167,0.235437,1 GT:PL 1/1:221,205,0
chr6 31324512 . C A 3.14828 .